anilin + br2

THE REACTION BETWEEN PHENYLAMINE (ANILINE) AND BROMINE WATER

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This page looks at the reaction of the benzene ring in phenylamine (aniline) with bromine water. It explains why the amino group activates the ring.

Activation of the ring

The -NH₂ group attached to tướng the benzene ring in phenylamine has the effect of making the ring much more reactive than thở it would otherwise be. This is exactly the same as the effect of the -OH group in phenol if you have already come across that.

For example, phenylamine will react with an aqueous solution of bromine (bromine water) in the cold and in the absence of any catalyst. Unactivated rings will only react with bromine in the presence of a catalyst.

The lone pair on the nitrogen touches the delocalised ring electrons . . .

. . . and becomes delocalised with them:

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A benzene ring undergoes substitution reactions in which the ring electrons are attacked by positive ions or the slightly positive parts of molecules. In other words, it undergoes electrophilic substitution.

If you increase the electron mật độ trùng lặp từ khóa around the ring by involving extra electrons from the -NH₂ group, it becomes even more attractive to tướng incoming electrophiles. That's what happens in phenylamine.

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The directing effect of the -NH₂ group

The -NH₂ group has more activating effect on some positions around the ring than thở others (for reasons which go beyond UK A level). That means that incoming groups will go into some positions much faster than thở they will into others.

The net effect of this is that the -NH₂ group has a 2,4-directing effect. That means that incoming groups will tend to tướng go into the 2- position (next door to tướng the -NH₂ group) or the 4- position (opposite the -NH₂ group). You will get hardly any of the 3- isomer formed - it is produced too slowly.

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The reaction with bromine water

If bromine water is added to tướng phenylamine, the bromine water is decolourised and a white precipitate is formed. This is exactly lượt thích the reaction which happens with phenol.

The precipitate is 2,4,6-tribromophenylamine.

Notice the multiple substitution around the ring - into all the activated positions. (The 6- position is, of course, just the same as the 2- position. Both are next door to tướng the -NH₂ group.)

Since both phenol and phenylamine decolourise bromine water and give a white precipitate, how can you distinguish between them?

First, of course, they look entirely different. Phenylamine is usually a brownish oil, whereas phenol has white crystals smelling of disinfectant.

If you want a simple chemical test, test their solubilities in sodium hydroxide solution and in dilute hydrochloric acid. Phenol is slightly acidic and ví reacts with sodium hydroxide solution to tướng give a colourless solution. Phenylamine is slightly basic and ví reacts with dilute hydrochloric acid to tướng give a colourless (or pale brown) solution.

Phenol would be no more soluble in dilute hydrochloric acid than thở it is in water. Similarly, phenylamine would be no more soluble in sodium hydroxide solution than thở it is in water.